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(G)=3G^2-2G+16
We move all terms to the left:
(G)-(3G^2-2G+16)=0
We get rid of parentheses
-3G^2+G+2G-16=0
We add all the numbers together, and all the variables
-3G^2+3G-16=0
a = -3; b = 3; c = -16;
Δ = b2-4ac
Δ = 32-4·(-3)·(-16)
Δ = -183
Delta is less than zero, so there is no solution for the equation
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